If 60 J of heat is added to an aluminum can with a mass of 24.7 g what is its temperature change Specific heat capacity of aluminum is 0.903 J g and 8728 C .?

To calculate the temperature change (( \Delta T )) of the aluminum can, we can use the formula ( Q = mc\Delta T ), where ( Q ) is the heat added, ( m ) is the mass, and ( c ) is the specific heat capacity. Rearranging to find ( \Delta T ), we have ( \Delta T = \frac{Q}{mc} ). Substituting the values:

[ \Delta T = \frac{60 , \text{J}}{24.7 , \text{g} \times 0.903 , \text{J/g°C}} \approx 2.68 , \text{°C}. ]

Thus, the temperature change of the aluminum can is approximately 2.68 °C.