How do you prepare 0.02 M of HCl?

Preparing 1N HCl for 1L. 1N=1M in HCl. Conc. HCl= 12M

M1V1=M2V2

12*V1=1*1000

V1=1000/12

V1=83.33ml

1N HCl= 83.33ml of Conc. HCl in 1L of water

2N HCl= 167ml of Conc. HCl in 1L of water.