8.02 grams of solute in 861 grams of water lower the freezing point to -0.430 c?

The change in freezing point is -0.430°C. The molal freezing point depression constant for water is 1.86°C kg/mol. Calculate the molality of the solution using the formula: ΔTf = Kf * m. 8.02 g of solute in 861 g of water is equivalent to 8.02 / 58.44 = 0.1373 mol of solute.