The length of a rectangle is three times its width If the area of the rectangle is 147 what is its perimeter?

Write a a series of equations as follows

p=2l+2w (formula for perimeter)

a=l*w (Formula for area)

l=3w (fact given in the question)

a=147 (fact given in hte question)

We don't currently have enough information to solve the perimeter formula for this rectangle, so we begin with the area formula to get more information.

By substituteing 147 for the variable a and 3w for the variable l, we arrive at this equation:

147=w*3w

With only one variable, we can solve this equation by isolating w on one side as follows

147=3w2(Multiply w by w to combine like terms)

147/3=3w2/3 (divide both sides by 3)

49=w2

sqrt49=sqrtw2(square root of both sides)

7=w

We now know that the width of the rectangle is 7. We also know that the length is three times that, which is 21. We can substitute these values into the perimeter eequation as follows:

p=(2*7)+(2*21)

p=14+42

p=56

The perimeter of the rectangle is 56