How many dollar bills would cover a football field?

190,800. There are 6 dollar bills in one yard, which means that there are 36 in one yard squared. The dimensions of a football field are 53 yd by 100 yd, or 5300 yd. squared. You multiply 5300 by 36 to get 190,800 dollar bills.

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The above answer is wrong.

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Actually, US Federal Reserve Notes are 6.14" long, by 2.61" wide, or 16.0254 In². There are 1296 In² in a Yd².

When you divide the number of In² in a Yd², by the number of In² that a Dollar Bill covers (16.0254), you find that it would take almost $81 to cover a Yd² (80.8716163091093).

The true dimensions of a Professional Football (NFL) field are 360 Ft X 160 Ft, or 120 Yards X 53.333 Yards (the end zones are considered part of the "Field of Play"). Thus, the square yardage in an NFL field are 6,396 Yd². When we multiply the number of bills to cover a Yd² by the number of Square Yards in the field, we get this equation; 80.8716163091093 X 6396.

Answer: $517,254.86 (using $1 bills)

(517,254.857913063)