How do i write a 360 as a product of prime factors give your answer's in index notation?

To write 360 as a product of prime factors, first, perform its prime factorization. Start by dividing 360 by the smallest Prime number, 2: (360 ÷ 2 = 180), (180 ÷ 2 = 90), (90 ÷ 2 = 45). Next, divide 45 by the next smallest prime number, 3: (45 ÷ 3 = 15), (15 ÷ 3 = 5). Finally, 5 is a prime number itself. Thus, the prime factorization of 360 is (2^3 \times 3^2 \times 5^1).