What is the perimeter and area of a rectangular room that is 12.2 ft long 8.9 ft wide?

The perimeter of a rectangle is calculated by adding all four sides together. For a rectangle with a length of 12.2 ft and a width of 8.9 ft, the perimeter would be 2(12.2) + 2(8.9) = 24.4 + 17.8 = 42.2 ft. The area of a rectangle is found by multiplying the length by the width. So, for this rectangular room, the area would be 12.2 ft x 8.9 ft = 108.58 square feet.