34 Use the pythagorean equation for a right triangle let x be one leg of the triangle, so the hypotenuse would be 2x +2 , and the other leg is 30 so using the equation we get: x2 + 302 = (2x+2)2 x2+900 = 4x2+8x+4 Rearranging, we get 3x2+8x-896 = 0 Using the quadratic equation we can solve for x, x = {-b +/- SQRT(b2-4ac)}/2a x = {-8 +/- SQRT(82-4(3)(-896))}/2(3) x = 16, and -18.667 but we can eliminate the negative answer so the hypotenuse will be 2*(16) + 2 or 34
Copyright © 2026 eLLeNow.com All Rights Reserved.