In a right triangle one of the acute angles is five times as large as the other acute angle Find the measure of the two acute angles?

Suppose the two acute angles are A and B degrees, where A = 3B.

then A+B = 90 (since the sum of all three angles is 180)

that is, 3B+BA=90 or 4B=90 => B=22.5 and then A= 3*22.5 = 67.5