What are the x-intercepts of the parabola x2 4x 12?

To find the x-intercepts of the parabola described by the equation (x^2 + 4x - 12 = 0), we can use the quadratic formula (x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}). Here, (a = 1), (b = 4), and (c = -12). Calculating the discriminant (b^2 - 4ac) gives (16 + 48 = 64). Therefore, the x-intercepts are (x = \frac{-4 \pm 8}{2}), resulting in (x = 2) and (x = -6).