A game board has 8 cards and 2 say WIN. Mayela picks 2 cards without replacing the first. What is the probability that neither say WIN?

To find the probability that neither of the two cards Mayela picks says WIN, we first note that there are 8 cards in total, with 2 WIN cards and 6 non-WIN cards. The probability that the first card she picks is not a WIN card is 6/8 (or 3/4). After picking one non-WIN card, there are 7 cards left, with 5 of those being non-WIN cards. The probability that the second card is also not a WIN card is 5/7. Thus, the overall probability that neither card says WIN is (6/8) * (5/7) = 30/56, which simplifies to 15/28.