How do you factor x to the third power plus 125?

x^(3) + 125 =>

x^(3) + 5^(3)

This factors to

(x + 5)(x^(2) - 5x + 5^(2) ) or (x + 5)(x^(2) - 5x + 25)

NB The clue is to spot that the constant (125) is a cubic numbers ( 5^(3)).

Similarly with other 'cubic factorings'.