What is the pressure that is exerted at the base of one cubic foot of water?

The pressure exerted at the base of one cubic foot of water can be calculated using the formula ( P = \rho g h ), where ( \rho ) is the density of water (approximately 62.4 lb/ft³), ( g ) is the acceleration due to gravity (about 32.2 ft/s²), and ( h ) is the height of the water column (1 foot in this case). Thus, the pressure at the base is approximately 62.4 pounds per square foot (psf), as the weight of the water directly translates to pressure exerted over the area. This pressure corresponds to roughly 0.43 psi (pounds per square inch).