The combustion of acetylene (C2H2) can be represented by the balanced chemical equation: (2 \text{C}_2\text{H}_2 + 5 \text{O}_2 \rightarrow 4 \text{CO}_2 + 2 \text{H}_2\text{O}). From this equation, 2 moles of C2H2 produce 4 moles of CO2. Therefore, 7.0 moles of C2H2 will produce (7.0 , \text{mol} \times \frac{4 , \text{mol CO}_2}{2 , \text{mol C}_2\text{H}_2} = 14.0 , \text{mol CO}_2).
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