2026-07-14 02:35
Use the Henderson-Hasselbalch equation:
[H+] = Ka * [HA] / [A-]
where
and
[H+] = Ka * [HA] / [A-] = (4.7*10-4) * (0.15) / (0.20) = 3.5*10-4 ,
so :
pH = -log[H+] = -log(3.5*10-4) = 3.45
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