Since ( y ) varies directly as ( x ), we can express this relationship as ( y = kx ), where ( k ) is the constant of variation. Given that ( y = 75 ) when ( x = 5 ), we can find ( k ) by substituting these values: ( 75 = k(5) ), which gives ( k = 15 ). Thus, the equation is ( y = 15x ). When ( x = 1 ), substituting gives ( y = 15(1) = 15 ).
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