A gas in a sealed container has a pressure of 125 kPa at a temperature of 30.0 degrees celsius If the pressure in the container is increased to 201kPa what is the new temperature?

Using the ideal gas law (P1/T1 = P2/T2), we can set up the equation as: 125 kPa / (30.0 + 273.15 K) = 201 kPa / T2. Solving for T2, the new temperature would be approximately 57.7 degrees Celsius.