What is the molarity of a solution in which 51 grams of aluminum oxide Al2O3 is dissolved in 500 mL of solution?

Need moles aluminum oxide first.

51 grams Al2O3 (1 mole Al2O3/101.96 grams)

= 0.5002 moles Al2O3

======================Now,

Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters )

Molarity =0.5002 moles Al2O3/0.500 Liters

= 1.0 M Al2O3 solution

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