When the lesser of two consecutive integers is added to three times the greater the result is 43 Find the integers?

Let the two integers be m-1 & m, so the lesser integer is m-1, and the greater integer is m:

(m-1) + 3*m = 43 --> 4*m -1 = 43 --> 4*m = 44, m = 11 & m-1 = 10, so 10 & 11

Check: 11 times 3 is 33, add 10 is 43