Why printf argument is not specified with and?

In C, the printf function uses a format string to determine how to display the arguments passed to it. The arguments are not specified with an ampersand (&) because printf requires the values of the variables, not their addresses. When passing variables to printf, their values are automatically accessed, which is why you simply provide the variable names without the address-of operator. This allows printf to correctly interpret and format the output based on the specified format string.