How many moles of krypton are there in 6.11 L of the gas at 802 atm and 31 degrees celsius?

802 atmospheres? You sure? Anyway, the formula is the important thing.

Use the ideal gas equation/law.

pressure atm * volume Liters = moles * R * temperature Kelvin

PV = nRT

31 degrees Celsius = 304.15 Kelvin

(802 atm)(6.11 Liter) = n(0.08206 L*atm/mol*K)(304.15 K)

4900.22 = 24.959n

= 196 moles of Krypton

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