The formula you are looking for is I = KVA x 1000/1.73 x E, I = 35 x 1000 = 35000/1.73 x 220 = 381, 35000/381 = 92 amps on the primary side.
35000/1.73 x 480 = 830, 35000/830 = 42 amps on the secondary.
Transformer conductors need to be rated at 125% so the primary will need an ampacity of 92 x 125% = 115.
A #3 copper conductor with an insulation factor of 90 degrees C is rated at 115 amps.
The secondary conductors will need an ampacity of 42 x 125% = 53 amps
A #8 copper conductor with an insulation factor of 90 degrees C is rated at 55 amps.
Copyright © 2026 eLLeNow.com All Rights Reserved.