If the sum of three numbers is 98 and the ratio of the first one to the second is 2 to 3 ans the ratio of the second to third is 5 to 8 what is the value of the second number?

Let number 1 be: X

number 2 be: Y number 3 be: Z X+Y+Z=98 3X=2Y 8Y=5Z Therefore by substituting you get: 12X=5Z

X+(3/2)X+(12/5)X= 98 10X+15X+24X=980 49X=980; X=20 Then 3(20)=2Y; Y=30 And 12(20)=5Z; Z=48

== == == == 1st number = 20

2nd number = 30

3rd number = 48 Sum of the numbers = 98 1st:2nd = 2:3

2nd:3rd = 5:8 This reallyy doesn't help me!!! ): help, help, help!!!!