Write an equation of the line that is perpendicular to the line Y 2x-11 and passes through the point 0 -7?

To find the equation of the line perpendicular to ( y = 2x - 11 ), we first determine the slope of the original line, which is 2. The perpendicular slope is the negative reciprocal, giving us a slope of ( -\frac{1}{2} ). Using the point-slope form ( y - y_1 = m(x - x_1) ) with the point (0, -7), we have:

[ y + 7 = -\frac{1}{2}(x - 0) ]

Simplifying, the equation becomes:

[ y = -\frac{1}{2}x - 7 ]