The specific heat capacity of lead is 0.128 J/g°C. To calculate the heat energy needed to raise the temperature of the lead by 250°C, you would use the formula: Q = m x c x ΔT, where Q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Plugging in the values, the heat energy needed would be 6400 Joules.
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