In how many ways can a family of mother and father and 4 children stand in a row to be photographed if the mother and father stand at the ends of the row?

To solve this problem, we first fix the mother and father in the two end positions. There are 2 ways to arrange them (mother on the left and father on the right, or vice versa). The 4 children can then be arranged in the 4 middle positions in (4!) (which is 24) different ways. Therefore, the total number of arrangements is (2 \times 4! = 2 \times 24 = 48) ways.