If 2 is the zero of 2x square plus px 14 find the value of p?

In a quadratic equation of the form ax^2 + bx + c = 0, if a is not equal to zero, then the zeros of the equation can be found using the formula x = (-b ± √(b^2 - 4ac)) / 2a. In this case, the zero is given as 2. Therefore, we can substitute x = 2 into the equation to get 2(2)^2 + p(2) + 14 = 0. Solving this equation will give us the value of p.