How many moles of sodium hydroxide are used for the tiltration if 17.65 mL of a 0.110 M sodium is needed to titrated 25.00 mL of a hydrochloride acid solution?

I need to see the balanced equation to work!

NaOH + HCl --> NaCl + H2O ( good, all one to one )

Now, find molarity HCl ( sodium, or sodium hydroxide; no matter )

(17.65 mL)(0.110 M NaOH) = (25.00 mL)(X M HCl)

= 0.07766 M HCl

-------------------------now,

Molarity = moles of solute/Liters of solution ( 25.00 mL = 0.025 L)

0.07766 M HCl = X moles/0.025 Liters

= 0.001942 moles HCl

---------------------------------------formal set up, though not needed

0.001942 moles HCl (1 mole NaOH/1 mole HCl)

= 0.00194 moles sodium hydroxide used

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