The perimeter of a rectangular playing field is 244 feet If its length is 2 feet longer than twice its width what are the dimensions of the field?

The answer is W=40 and L=82

If you're wondering how to solve it, then let "P" represent perimeter "L" represent length and "W" represent width.

P=2L+2W

L=2W+2

244=2(2W+2)+2W

244=4W+4+2W

244=6W+4

6W=244

244/6W=

W=40

Now plug the 40 in for w in: L=2W+2

L=2(40)+2

L=80+2

L=82

final answer: L=82 and W=40