The sum 9 + 99 + 999 + 9999 + 99 999 + ....
where the last number to be added consists of nine digits of 9 becomes:
(10 – 1) + (100 – 1) + (1000 – 1) + (10 000 – 1) + ...
where the last multiple of 10 has nine zeros.
There are nine pairs of brackets altogether.
Add the multiples of 10 first and then subtract 9:
The digit 1 appears 9 times in the final answer.
Copyright © 2026 eLLeNow.com All Rights Reserved.