800 dollars invested at an annually compounded interest rate of 6 percent will be worth how much at the end of 10 years?

The equation is P=C(1+r)^t; where C is the money invested, r is the rate(change from percent to decimal form), and t is the time.

So plug in the numbers to get: P=800(1+.06)^10

The answer is 1432.678, I would round it to $1432.68