Suppose the rectangle has length L and width W where, as per convention, L >= W.
Now Perimeter = 22 = 2(L+W) so L+W = 11
L is a whole number >=11/2 ie L >= 6
Also, W>0 so L <= 10.
Thus L = 6,7,8,9,10 giving 5 possible areas for the rectangle.
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