Write a programme in C to find the union and intersection of two sets?

1 answer

Answer

1095863

2026-07-19 08:20

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#include<stdio.h>

#include<conio.h>

void Union(int set1[10],int set2[10],int m,int n);

void Intersection(int set1[10],int set2[10],int m,int n);

void main()

{

{

int a[10],b[10],m,n,i,j;

int ch;

clrscr();

printf("\nEnter the no of elements in first set:");

scanf("%d",&m);

printf("\nEnter the elements:");

for(i=0;i<m;i++)

{

scanf("%d",&a[i]);

}

printf("\nElement of First set:\n");

for(i=0;i<m;i++)

{

printf("\t%d",a[i]);

}

printf("\nEnter the no of elements in second set:");

scanf("%d",&n);

printf("\nEnter the elements:");

for(i=0;i<n;i++)

{

scanf("%d",&b[i]);

}

printf("\nElement of second set\n");

for(i=0;i<n;i++)

{

printf("\t%d",b[i]);

}

while(1)

{

printf("\n\tMenu\n\n1.Union\n2.Intersection");

printf("\n3.exit");

printf("\nenter your choice:-");

scanf("%d",&ch);

switch(ch)

case 1:

union(a,b,m,n);

break;

case 2:

intersection(a,b,m,n);

break;

case 3:

exit(0);

}

getch();

}

}

void union(int a[10],int b[10],int m,int n)

{

int c[20],i,j,k=0,flag=0;

for(i=0;i<m;i++)

{

c[k]=a[i];

k++;

}

for(i=0;i<n;i++)

{

flag=0;

for(j=0;j<m;j++)

{

if(b[i]==c[j])

{

flag=1;

break;

}

}

if(flag==0)

{

c[k]=b[i];

k++;

}

}

printf("\nElement of resultant set\n");

for(i=0;i<k;i++)

{

printf("\t%d",c[i]);

}

}

void intersection(int a[10],int b[10],int m,int n)

{

int c[20],i,j,k=0,flag=0;

for(i=0;i<m;i++)

{

flag=0;

for(j=0;j<n;j++)

{

if(a[i]==b[j])

{

flag=1;

break;

}

}

if(flag==1)

{

c[k]=a[i];

k++;

}

}

printf("\nElement of resultant set\n");

for(i=0;i<k;i++)

{

printf("\t%d",c[i]);

}

}

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