What is the slope intercept form of the equation of a line with a y intercept of -2 and parallel to the line 2x 3y9?

To find the slope-intercept form of a line parallel to the given line, we first need to determine the slope of the given line (2x + 3y = 9). Rewriting it in slope-intercept form (y = mx + b), we get (3y = -2x + 9) or (y = -\frac{2}{3}x + 3), so the slope (m) is (-\frac{2}{3}). Since parallel lines have the same slope, the equation of the new line with a y-intercept of -2 is (y = -\frac{2}{3}x - 2).