How can you solve log2?

To solve for ( \log_2(x) ), you need to determine the power to which 2 must be raised to yield ( x ). This can be rewritten in exponential form as ( 2^y = x ), where ( y = \log_2(x) ). If you need to calculate ( \log_2 ) of a specific number, you can use the change of base formula: ( \log_2(x) = \frac{\log_{10}(x)}{\log_{10}(2)} ) or ( \log_2(x) = \frac{\ln(x)}{\ln(2)} ) using natural logarithms.