Can you find both sides of a right triangle if only the perimeter and hypotenuse are given?

Let perimeter = 30 hypotenuse h = 13 find other 2 sides. a and b you know, h² = a² + b² = 169 a + b + h = 30 so a + b = 17 (a + b)² = 17² = 289 a² + b² + 2ab = 289 169 + 2ab = 289 ab = 60 from this a = 60/b a = (17 - b) = 60/b 17b - b² = 60 b² - 17b + 60 = 0 (b - 12)(b - 5) = 0 b = 12 or b = 5 a = 5 or a = 12 ---------