11.37 mg KI in 103.0 mL of solution?

To find the molarity of the potassium iodide (KI) solution, first convert the mass of KI into moles. The molar mass of KI is approximately 166 g/mol, so 11.37 mg (or 0.01137 g) corresponds to about 0.0000683 moles of KI. Next, divide the number of moles by the volume of the solution in liters (0.103 L) to find the molarity. Thus, the molarity of the KI solution is approximately 0.000663 M.