How do you solve a sum of money divided among three persons x y z in the ratio 10 7 5if y gets 14 more than z how much will x get and what is the total sum of money?

Let the amounts received by x, y, and z be represented as 10k, 7k, and 5k, respectively. According to the problem, (7k = 5k + 14), which simplifies to (2k = 14), giving (k = 7). Therefore, x receives (10k = 10 \times 7 = 70) and the total sum of money is (10k + 7k + 5k = 22k = 22 \times 7 = 154). Thus, x gets 70, and the total sum is 154.