How would you find the perpendicular distance from the point 7 5 to the line 3x plus 4y -16 equals 0 on the Cartesian plane?

Equation of line: 3x+4y-16 = 0 or y = -3/4x+4

Slope of line: -3/4

Slope of perpendicular line: 4/3

Perpendicular equation: y-5 = 4/3(x-7) or 3y = 4x-13

Both equations intersect at: (4, 1)

Perpendicular distance from (7, 5) to (4, 1) = 5 units using distance formula