Well, we would have to know how many % of the coding sequence would be exons and introns, but let's ignore this and assume 100% of the sequence are exons;
129 aminoacids = 129 codons = 129*3 nucleotides = 387 nucleotides.
10 pairs of bases = 3,4 nm;
387/10 = 38,7
38,7 * 3,4 = 131,58 nm.
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