A committee of 5 people must be selected from 5 accountants and 8 educators in how many ways can a selection be done if there are at least 3 educators in the committee?

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1277246

2026-07-30 23:35

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Well, honey, if you want a committee with at least 3 educators out of 5 members, you can choose 3 educators out of 8 in 8 choose 3 ways, and then fill the remaining 2 spots with any of the remaining educators or Accountants. So, that gives you 8 choose 3 * 5 choose 2 ways, which is 56 * 10 = 560 ways to create your sassy little committee.

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