A golfer strikes a golf ball at an angle 17 degree above the horizontal. with what velocity must the ball be struck in order to reach the green which is a horizontal distance of 250m from the golfer.?
To solve this problem you use the derived formula ∆dh=(V1h2(sin2Ѳ))/g 250m=V1h2(sin2(17))/9.8m/s2 V1h=((sin(17))/9.8m/s2)1/2 V1h= 64.7292201m/s V1h= 65m/s
