When 90 kJ is removed from a 2-kg copper bar its temperature drops from 200 degrees Celsius to 85 degrees Celsius what is the specific heat of the iron?

q( Joules) = mass grams * specific heat * change in temperature

90 kj = 90000 Joules

2 kg = 2000 grams

90000 Joules = (2000 g)( SP )(200 C - 80 C)

90000 = 240000(SP)

0.375 J/gC

( The actual specific heat of copper is 0.385 J/gC, so close enough for the problem type )