What is the percent yield of h2o if 58g h2o are produced by combining 60g o2 and 7g h2?

Balanced equation.

2H2 + O2 >> 2H2O ( now find limiting reactant )

7 grams H2 (1 mole H2/2.016 grams) = 3.472 moles H2

60 grams O2 (1 mole O2/32 grams) = 1.875 moles O2

1.875 moles O2 (2 mole H2/1 mole O2) = 3.75 mole H2 ( checked O2, but I know H2 limits because you do not have 3.75 moles H2, so H2 drives reaction)

3.472 moles H2 (2 mole H2O/2 mole H2)(18.016 grams/1 mole H2O)

= 62.552 grams H2O produced, so;

58 grams/62.552 times 100

= 92.7% yield of H2O, call it 93%