The product of 3 consecutive odd numbers is 12075 find the numbers?

Let n be an integer. 2n - 1 will be odd.

(2n - 1) * (2(n+1) - 1) * (2(n+2) - 1) = 12075

4n^3 + 6n^2 - n - 6039 = 0

Which has 1 real root and 2 complex conjugate roots.

The real root is at n=11.

Substituting back in: 2(11) - 1 = 21

Final answer:

21 * 23 * 25 = 12075