What is the probability of not getting a 7 or 11 on either of two tosses of a pair of dice?

First we find the probability of getting a 7. Of the 36 outcomes possible 6 result in a sum of 7, in other Words 1/6. The probability of getting an 11 is 2/36 or 1/18. The probability of getting one or the other is the sum of the two, 8/36 or 2/9. The proability of getting neither is equal to the probability of getting anything other than 7 or 8. We find this value by subtracting 2/9 from 1. So the probability of not getting 7 or 11 is 7/9.